Answer:
Step-by-step explanation:
let : x The length and y the width you have this system :
xy =60....(1)
x = y+10...(2)
put the value for x in (1): (y+10)y =60
the quadratic equation is : y² +10y - 60 = 0
Δ =b² - 4ac a = 1 b= 10 c= - 60
Δ =10² - 4(1)(-60) = 324 =18²
y 1 = (-10-18)/2 negatif...... refused
y 2 = (-10+18)/2 =4
the width is 4
Answer:
D
Step-by-step explanation:
substitute t=-3 in the equation
3(-3) squared +5(-3)+6=18

Both the numerator and denominator are continuous at

, which means the quotient rule for limits applies:

Perhaps you meant to write that

instead? In that case, you would have
Answer:
The probability will be "0.0111".
Step-by-step explanation:
The given values are:
Mean,
= 79
Standard deviation,
= 3.5
Now,
⇒ 


⇒ 
So,
= ![1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x} < \frac{(81 - 79) }{0.875} ]](https://tex.z-dn.net/?f=1%20-%20P%7B%5Cfrac%7B%28%5Cbar%20x%20-%20%5Cmu%20%5Cbar%20x%20%29%7D%7B%20%5Csigma%20%5Cbar%20x%7D%20%20%3C%20%5Cfrac%7B%2881%20-%2079%29%20%7D%7B0.875%7D%20%5D)
= 
= 