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3 years ago

If D + E = 7, and 2D + 2E + 8J = 19, then what is J?

Mathematics

1 answer:

poizon [28]3 years ago

3 0

Answer:

Technically, you'd have to solve that, I'm sorry.

Step-by-step explanation:

19/8 - d/4 - e/4

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What is the minimum value for h(x)=x2−16x+60?

iogann1982 [59]

Minimum value is equal to x=8, y=-4
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value.

3 0

3 years ago

The circle below is centered at (10,4) and has a radius of 4. What it’s equation?

Rina8888 [55]

Answer:

$(x-10)^2 + (y-4)^2 = 16$

Step-by-step explanation:

To write the equation using a center and a radius, use the vertex form of the equation.

$(x-h)^2+(y-k)^2 = r^2$

Substitute the values h=10 and k=4 into the equation along with r = 4.

$(x-10)^2 + (y-4)^2 + 4^2\\(x-10)^2 + (y-4)^2 = 16$

5 0

3 years ago

The ratio of boys to girls is 4:3 .T here are 35 students in a class how many students are boys ?? Pleaseee help

evablogger [386]

There are 20 boys in the class. The ratio is 4:3 so that means 4 out of 7 are boys and 3 out of 7 are girls. Divide 35 by 7 and you get 5. 5 times 4 is 20. 5 times 3 is 15. add them together and you have 35 students in total. So 20 students are boys and 15 students are girls.

8 0

3 years ago

Rectangle JKLM is shown.

ad-work [718]

Answer:

Step-by-step explanation:

We can use the Pythagorean theorem to solve this.

(13)^2 = (8)^2+x^2

169 = 64 + x^2

x^2 = 105

x is approximately 10.2, so B

6 0

3 years ago

The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi

pshichka [43]

Answer:

$E(\bar{x}) = 28520$

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

$E(\bar{x}) = \mu = 28520$

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689$

7 0

3 years ago