You'll need to use parentheses to indicate what is under the first radical sign and what is not. Did you mean radical(36a) or just radical 36?
I will assume that you meant radical(36a).
Then you have [radical(36a}*(b^4)*c^5.
This comes out to 6sqrt(a)*b^4*c^5.
1. 32u is the same as A, B and D but not C
2. True because 32 less than s is the same as s take away 32
I think it 3 bit I am not sure
Answer: System 1 has an infinite number of solutions and System II has no solutions.
Step-by-step explanation:
If we look at system 1, we see that if we multiply the first equation by 2 and subtract the y value so that its on the same side as x, the equations are the same. That means that no matter the x or y value, it will be a solution.
If we look at system 2, however, we see that if we multiply the top equation by 3, the equations are the exact same except for the fact that the top equation has a -21. This means that no matter the x or y, there will never be a solution.
