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FinnZ [79.3K]
3 years ago
15

Which measurement is the best estimate for the length of a bean?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0
The best estimate for the length of a bean would be B: 13 cm
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Is 18% larger than 0.7
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Tell whether the triangle with the given side lengths is a right triangle.
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6 0
3 years ago
HELP!
Anastasy [175]

The areas of the parallelograms can be compared as: A. The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

<h3>What is a parallelogram?</h3>

A parallelogram refers to a geometrical shape and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

<h3>How to calculate the area of a triangle?</h3>

Mathematically, the area of a triangle can be calculated by using this formula:

Area = ½ × b × h

Where:

  • b represents the base area.
  • h represents the height.

<h3>How to calculate the area of a rectangle?</h3>

Mathematically, the area of a rectangle can be calculated by using this formula;

A = LW

Where:

  • A represents the area of a rectangle.
  • l represents the length of a rectangle.
  • w represents the width of a rectangle.

Next, we would determine the area of the two parallelograms as follows:

Area of parallelogram 1 = Area of red-rectangular figure - Area of triangle A - Area of triangle B - Area of triangle C - Area of triangle D.

Substituting the given parameters into the formula, we have;

Area of parallelogram 1 = (6 × 6) - (½ × 4 × 2) - (½ × 2 × 4)- (½ × 4 × 2) - (½ × 2 × 4)

Area of parallelogram 1 = 36 - 4 - 4 - 4 - 4

Area of parallelogram 1 = 36 - 16

Area of parallelogram 1 = 20 units².

For parallelogram 2, we have:

Area of parallelogram 2 = Area of blue-rectangular figure - Area of triangle P - Area of triangle Q - Area of triangle R - Area of triangle S.

Substituting the given parameters into the formula, we have;

Area of parallelogram 2 = (8 × 4) - (½ × 2 × 2) - (½ × 6 × 2)- (½ × 2 × 2) - (½ × 2 × 6)

Area of parallelogram 2 = 32 - 2 - 6 - 2 - 6

Area of parallelogram 2 = 32 - 16

Area of parallelogram 2 = 16 units².

Difference = Area of parallelogram 1 - Area of parallelogram 2

Difference = 20 - 16

Difference = 4 units².

In conclusion, we can infer and logically deduce that the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

Read more on parallelogram here: brainly.com/question/4459854

#SPJ1

6 0
1 year ago
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