Let us add consecutive odd numbers and try to find any relationship.
1. 1
2. 1+3 = 4 ( square of 2 i.e 
)
3. 1+3+5 = 9 ( 
)
4. 1+3+5+7 = 16 (
)
5. 1+3+5+7+9 = 25 (
)
6. 1+3+5+7+9+11 = 36 ( 
)
7. 1+3+5+7+9+11+13 = 49 (
)
If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to . The sum of the numbers in the fifth line is equal to .
118.73 that's the answer, you have to use long multiplication. Hope I helped
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hope that helped :)
Answer:
sqrt(sqrt(x))
Step-by-step explanation:
The problem statement tells you how to do it: take the square root, then the square root of that, using the square root function twice and making the result of one the argument of the other.
