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Lunna [17]
3 years ago
7

!!!!!!!50 points!!!!!!!! QUESTION BELLOW HELP ASAP!!!!!!!!!

Mathematics
2 answers:
kozerog [31]3 years ago
8 0
Well for this question you can factor like this:
7^3(7^3 + 7^2 -7) = 7^3(385) = 7^3(35)(11) = 7^3(7)(5)(11) = 7^4(5)(11) :)))
I hope this is helpful
have a nice day 
kirza4 [7]3 years ago
4 0
Hmm, interesting
one way would be to multply it out or set it equal to 11x where x is a whole number (if x is not a whole number, then it is not divisible)
11x=7^6+7^5-7^4
undistribute 7^4
11x=(7^4)(7^2+7^1-1)
11x=(7^4)(49+7-1)
11x=(7^4)(55)

56=5*11

11x=(7^4)(5)(11)
divide by 11
x=5(7^4)



aka, find if 11 is a factor of that number


x=5(7^4)
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Step-by-step explanation:

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equate right sides of these two equations:

4x+6=2x-4

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