A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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Answer:
1 solution
Step-by-step explanation:
y=16, r=-21/2
Answer:
Step-by-step explanation:
you want to multiply y by 2 or divide by 1/2
? = 1/2 in this problem
Answer:
15/2
Step-by-step explanation:
Answer:
x=−7/5and y=−6/5
Step-by-step explanation:
Step: Substitute−2x−4foryiny=3x+3:
y=3x+3
−2x−4=3x+3
−2x−4+−3x=3x+3+−3x(Add -3x to both sides)
−5x−4=3
−5x−4+4=3+4(Add 4 to both sides)
−5x=7
−5x
−5
=
7
−5
(Divide both sides by -5)
x=−7/5
