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Fantom [35]
3 years ago
15

If the perimeter of a triangle is 10x + 5y and two of the sides are 3x + 4y and 5x − y, which is the third side? A. 2x + 2y B. 2

x + y C. −2x + 2y D. x + 2y
Mathematics
1 answer:
Vlad [161]3 years ago
5 0
The measures of two sides of a triangle are 3x + 4y and 5x - y. If the perimeter is 10x + 5y, find the measure of the third side. 

<span>Let measure of the 3rd side be 'b'. </span>

<span>Substitute the values of length of the two sides and perimeter in equation and solve for b. </span>

<span>So, 10x + 5y = 3x + 4y + 5x - y + b..........[Substitute the values] </span>
<span>10x + 5y = 8x + 3y + b </span>
<span>(10x + 5y) - (8x + 3y) = b </span>
<span>10x + 5y - 8x - 3y = b </span>
<span>10x - 8x + 5y - 3y = b </span>
<span>2x + 2y = b </span>

<span>So, the measure of the third side is 2x + 2y. </span>
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6 0
3 years ago
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
3 years ago
In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
Ms. Medina's math class has 15 students in total. In her class 9 of the students are boys. Which
PIT_PIT [208]

Answer:

6

Step-by-step explanation:

15 - 9

6 0
3 years ago
If a polynomial function f(x) has roots 4 - 13 and 5, what must be a factor of f(x)?
Alla [95]

Answer:

I believe its C

amsc:dherbo00

Step-by-step explanation:

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