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Fudgin [204]
3 years ago
9

Type your answer in the box. You may use numbers, a decimal point (.), and/or a negative sign (-) in your answer. Stella is rent

ing a car for a business trip. The car rental agency charges a flat rate of $60 plus $0.50 per mile for every mile she drives over 40 miles. Stella’s company will pay up to $270, excluding the cost of gasoline, for the use of the rental car. What is the greatest number of miles Stella can drive the rental car without spending more than $270?
Mathematics
1 answer:
True [87]3 years ago
5 0
420 blaze it 


420 miles
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1) A light bulb producing company states that its lights will last an average of 1200 hours with a standard deviation of 200 hou
Ronch [10]

The mean ( average ) is given as 1200 hours.

The standard deviation is 200, sample size is 100.

Find the standard error:

√(200^2 / 100) = 20

Now calculate the confidence interval. For 95% the Z number is 1.96

Multiply Z by the standard error:

1.96 x 20 =39.2

Now find the range that the mean should be within:

1200 - 39.2 = 1160.8

1200 + 39.2 = 1239.2

The samples should be between 1160.8 and 1239.2 for a 95% confidence interval.

Since the average was 1050, which is below 1160.8 the bulbs are not in compliance.

4 0
3 years ago
I need help finding x≈.... this is for a important grade so pls help really ​
gulaghasi [49]

Answer:

the answer is 40 X=40

hope this helps :)

3 0
3 years ago
Roxanne has $80 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much will she have
finlep [7]
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3 0
3 years ago
73.18 minus 5 .23 multiply 9.34​
maks197457 [2]

Answer: 634.653

I don't know if this is right or not, but i hope this helps

4 0
3 years ago
Read 2 more answers
What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?
tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

y=x^{2}-8x+15

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

x^{2}-8x+15=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-8x+15=0  

so

a=1\\b=-8\\c=15

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}

x=\frac{8\pm\sqrt{4}} {2}

x=\frac{8\pm2} {2}

x=\frac{8+2} {2}=5

x=\frac{8-2} {2}=3

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0
3 years ago
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