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3241004551 [841]
3 years ago
12

Toys R Us is having a 38% off

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

It'd be $13.64 or $14.00

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You purchase an item to sell in your store. The item costs you $6.45. You mark the item up 20%, but later run the item on sale a
wel
Answer: The customer paid 7.81 <<<<=====


5 0
3 years ago
What expression represents the area of a circle with a radius of 7 units
Gwar [14]

Answer:

The area of the circle is 153.86 u²

And the expression is

a = π * (7 u)²

Step-by-step explanation:

To solve this problem we need to use the area formula of a circle:

a = area

r = radius = 7 units

π = 3.14

a = π * r²

we replace with the known values

a = π * (7 u)²

a = 3.14 * 49 u²

a = 153.86 u²

The area of the circle is 153.86 u²

4 0
3 years ago
Can someone plz help me find the answer to 2x=4 y-16. and 2x-y=-7
telo118 [61]

Answer:

So, y = 2x + 7;

Then, 2x = 4( 2x + 7 ) - 16;

2x = 8x + 28 - 16;

2x = 8x + 12;

- 6x = 12;

x = - 2;

Then, y = 2· (-2) + 7;

y = - 4 + 7;

y = 3.

Step-by-step explanation:


8 0
4 years ago
Find the length of side x in the simplest radical form with a rational denominator.
lisov135 [29]

Answer:

sq root of 6 divided by 2

Step-by-step explanation:

use pythagorean theorem: square of each leg equals the square of the hypotenuse

x squared plus x squared = radical three squared

2x² = 3

x² =  \frac{3}{2}

x = square root of 3/2

rationalize the denominator to get sq root of 6 divided by 2

6 0
3 years ago
Which expression is equivalent to sin(1.8x) sin(0.5x)?
Rasek [7]
Hum, this problem was difficult. You use the next expression to solve this problem. \[\cos (A - B) = \cos A \cos B + \sin A \sin B \] \[\cos (A + B) = \cos A \cos B - \sin A \sin B\] \[\cos (A - B ) - \cos (A +B ) =2 \sin A \sin B\] So \[\sin A \sin B = 0.5 \left( \cos(A - B) - \cos(A + B) \right)\] A = 1.8 x, B = 0.5 x \[\sin (1.8x) \sin (0.5x) = 0.5\left( \cos(1.8-0.5)x - \cos(1.8+0.5)x \right)\]\[= 0.5 \left( \cos(1.3x) - \cos (2.3x) \right)\] It's finish !!
3 0
3 years ago
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