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r-ruslan [8.4K]
3 years ago
8

HELP PLEASE ASAP???!!!!!! !!!!

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

your answer is C

Step-by-step explanation:


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I need help with this math problem
Mkey [24]

Step-by-step explanation:

that is just a complicated way to ask, at what values of x is the functional value infinite ? or directly, for what values of x is the denominator of that fraction 0 ?

it is zero, if just one of the 3 factors is 0.

and that would happen for

x = 0

x = -6

x = 1

so, A, D and E are correct.

8 0
2 years ago
What is the slope of the line between (3, −4) and (−2, 1)? (1 point)
stealth61 [152]
-1 will be your answer

rise over run
3-1 = 2
-4 + 1 = -3
2-1 = 1
-3 + 1 = -2


hope this helps
8 0
3 years ago
Which term does not belong with the other three?
Brrunno [24]

Answer:

The one that does not belong has a different number of dimensions.

Step-by-step explanation:

<u>Given list consists of:</u>

  • a line segment (AB)
  • a plane (CDE)
  • a line (FG)
  • a ray (HI)

Three of them have one dimension but the plane has two dimensions,

therefore<u> </u>the plane in the list does not belong with the other three.

<u>So correct answer choice is:</u>

  • The one that does not belong has a different number of dimensions.

6 0
3 years ago
Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
3 years ago
Read 2 more answers
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-ax
KIM [24]

Answer:

3

Step-by-step explanation:

f(x)=a*b^x - is a formula of exponential function

As we know the point (x=0; y=3) lies at the function's  graph.

So we have to put in formula f(x)=a*b^x   x=0  f(x)=y=3

3=a*b^0   (b^0=1) => 3=a*1 => 3=a  

6 0
3 years ago
Read 2 more answers
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