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Luda [366]
3 years ago
10

Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Mathematics
2 answers:
Sergio [31]3 years ago
8 0
\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)




sweet-ann [11.9K]3 years ago
4 0

Answer:

d on edge

Step-by-step explanation:

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9966 [12]

Answer:

D E + E F greater-than D F

5 less-than D F less-than 13

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Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

we have the triangle EDF

where

ED=4\ units\\EF=9\ units

<u><em>Applying the triangle inequality theorem</em></u>

1)

ED+EF > DF\\4+9 > DF\\13 > DF\\DF < 13\ units

2)

ED+DF > EF\\4+DF > 9\\DF > 5\ units

so

The length of DF is the interval -----> (5,13)

The triangle DEF is a scalene triangle (the three length sides are different)

therefore

<em>The statements that are true are</em>

D E + E F greater-than D F

5 less-than D F less-than 13

Triangle D E F is a scalene triangle

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