Answer:
There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.
To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.
Step-by-step explanation:
Suppose the equation of the straight line that passes through E and F is this:
y = 7x + 2
We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.
10 = 7(1) + 2 = 7 + 2 = 9
10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.
If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.
Answer: 4.F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).
Hope this helps :)
C it’s very easy if you want me to explain I will
Answer:
D.
Step-by-step explanation:
120=x+y and 10=.05x+.10y
120-x=y then subsitute 10=.05x+.10(120-x) distruibte and solve you can do it feel free to go off of my math.
x(nickels) y(dimes)
