n < 0, is another way to say "n is negative", so let's check
![\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a^n~\hspace{10.5em}\stackrel{n = -n}{a^{-n}}\implies \cfrac{1}{a^n} \\\\\\ a^{-n}~\hspace{10em}\stackrel{n=-n}{a^{-(-n)}}\implies a^{+n}\implies a^n](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bnegative%20exponents%7D%0A%5C%5C%5C%5C%0Aa%5E%7B-n%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5Cqquad%20%5Cqquad%0A%5Ccfrac%7B1%7D%7Ba%5En%7D%5Cimplies%20a%5E%7B-n%7D%0A%5Cqquad%20%5Cqquad%0Aa%5En%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B-n%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0Aa%5En~%5Chspace%7B10.5em%7D%5Cstackrel%7Bn%20%3D%20-n%7D%7Ba%5E%7B-n%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5C%5C%5C%5C%5C%5C%0Aa%5E%7B-n%7D~%5Chspace%7B10em%7D%5Cstackrel%7Bn%3D-n%7D%7Ba%5E%7B-%28-n%29%7D%7D%5Cimplies%20a%5E%7B%2Bn%7D%5Cimplies%20a%5En%20)
Answer:
The solution is (1,2)
Step-by-step explanation:
- 2x - y = - 4
x + 2y = 5
Multiply the second equation by 2 so we can eliminate x
2( x + 2y) = 5*2
2x +4y = 10
Add this to the first equation
- 2x - y = - 4
2x +4y = 10
----------------------
3y = 6
Divide each side by 3
3y/3 = 6/3
y = 2
- 2x - y = - 4
x + 2y = 5
Multiply the first equation by 2 to eliminate y
2(- 2x - y) = - 4*2
-4x -2y = -8
Add this to the second equation
-4x -2y = -8
x + 2y = 5
------------------
-3x = -3
Divide by -3
-3x/-3 = -3/-3
x = 1
The solution is (1,2)
About $5.26 will be deducted from $50
So he will get $44.74
Answer:
1. c
2. b
3. a
4. d
5. e
6. f
Step-by-step explanation:
Answer:
(1, -7)
Step-by-step explanation:
P(3,4)
3 up ---> y = 4 + 3 = 7
2 left ----> x = 3 - 2 = 1
new point (1, 7)
after 180 rotation around origin
point is (-1, -7)
now reflection over y-axis
(1, -7)
