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STatiana [176]
3 years ago
5

1/3+2/3m=2/3m-2/3 Does it have no solution or is it an identity?

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0
\dfrac{1}{3}+\dfrac{2}{3}m=\dfrac{2}{3}m-\dfrac{2}{3}\ \ \ \ \ |subtract\ \dfrac{2}{3}m\ from\ both\ sides\\\\\dfrac{1}{3}=-\dfrac{2}{3}\ \ \ \ FALSE\\\\Answer:\ No\ solution
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There was 5/8 of a pie left in the fridge. Daniel are 1/4 of the left over pie. How much of a pie did he eat
oee [108]

Answer:

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Step-by-step explanation:

1. Make it so 1/4 is an eighth so you can subtract it from 5/8.

1/4 x 2 = 2/8

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7 0
3 years ago
Read 2 more answers
Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
alekssr [168]

Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

                       = mod (25-75+0-75) ÷ 2

                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

4 0
3 years ago
What is 1/5 divided by 5/7
vampirchik [111]
1/5 divided by 5/7 is 7/25
1/5 ÷ 7/5 = 7/25

Your answer is 7/25


5 0
3 years ago
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