The first image has a coordinate of A'(1, 6) B'(-3, 7)
<h3>How to calculate the coordinates of an image after a translation?</h3>
Translation can be defined as movement in a straight line.
Given the rule: (x,y) → (x + 3, y - 1) and A(-2,7) B(-6,8)
That means: A(x = -2, y =7) B(x = -6, y = 8)
Thus the translation will be:
A'(-2 +3, 7-1) B'(-6+3, 8-1) = A'(1, 6) B'(-3, 7)
Therefore, the coordinate of the image is A'(1, 6) B'(-3, 7)
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If the original angle is x degrees then its supplement is 180 - x degrees.
we have the equation:-
180 - x = 3x + 20
160 = 4x
x = 40
The original angle is 40 degrees and its supplement is 140 degrees
Answer:
B = 34.2°
C = 58.2° or 121.8°
c= 10.6
Step-by-step explanation:
Step 1
Finding c
We calculate c using Pythagoras Theorem
c²= a² + b²
c = √a² + b²
a= 8, b = 7
c = √8² + 7²
c = √64 + 49
c = √(113)
c = 10.630145813
Approximately c = 10.6
Step 2
Find B
We solve this using Sine rule
a/sin A = b/sin B
A = 40°
a = 8
b = 7
Hence,
8/sin 40° = 7/sin B
8 × sin B = sin 40° × 7
sin B = sin 40° × 7/8
B = arc sin (sin 40° × 7/8)
B ≈34.22465°
Approximately = 34.2°
Step 3
We find C
Find B
We solve this using Sine rule
b/sin B = c/sin C
B = 34.2°
b = 7
c = 10.6
C = ?
Hence,
7/sin 34.2° = 10.6/sin C
7 × sin C = sin 34.2 × 10.6
sin C = sin 34.2° × 10.6/7
C = arc sin (sin 34.2° × 10.6/7)
C = arcsin(0.85)
C= 58.211669383
Approximately C = 58.2°
Or = 180 - 58.2
C = 121.8°
Answer:
step1 - distributive property
step2 - associative property
step3 - cumulative property
step4 - associative property
Step-by-step explanation:
