Consider a simple clock.
1 answer:
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Hello,
A=(4,2)
B=(2,8)
(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3
A=(4,2)
B=(2,8)
(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3
Answer:
Option C.
Step-by-step explanation:
By the property of unique triangles (ASA), one side is included between the two angles.
By this property, if included side of the triangle ABC is AB then this side will be included between the two angles A and B.
Therefore, is included between ∠A and ∠B.
Option C. will be the answer.