Answer:
65
Step-by-step explanation:
13x5 = 65
Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.
![P(A)=8\%](https://tex.z-dn.net/?f=P%28A%29%3D8%5C%25)
![P(B)=14\%](https://tex.z-dn.net/?f=P%28B%29%3D14%5C%25)
It is given that 6 students play on both teams.
![P(A\cap B)=\frac{6}{200}\times 100=3\%](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D%5Cfrac%7B6%7D%7B200%7D%5Ctimes%20100%3D3%5C%25)
We have to find the probability that a student plays either basketball or soccer.
![P(A\cup B)=P(A)+P(B)-(A\cap B)](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3DP%28A%29%2BP%28B%29-%28A%5Ccap%20B%29)
![P(A\cup B)=8\%+14\%-3\%](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3D8%5C%25%2B14%5C%25-3%5C%25)
![P(A\cup B)=19\%](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3D19%5C%25)
Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.
Answer:
The area of the garden is ![2356\ ft^2](https://tex.z-dn.net/?f=2356%5C%20ft%5E2)
Step-by-step explanation:
<u>Area of a Square</u>
Given a square of a side length of x, the area is calculated as:
![A = x^2](https://tex.z-dn.net/?f=A%20%3D%20x%5E2)
There is a square garden area of a side length of x=50 feet. The area is:
![A_1=50^2=2500\ ft^2](https://tex.z-dn.net/?f=A_1%3D50%5E2%3D2500%5C%20ft%5E2)
Inside of it, there is another square area for a fountain display of a side length of 12 feet. The area is:
![A_2=12^2=144\ ft^2](https://tex.z-dn.net/?f=A_2%3D12%5E2%3D144%5C%20ft%5E2)
The area of the garden is the difference between A2 and A1:
![A_g=A_2-A_1=2500\ ft^2-144\ ft^2](https://tex.z-dn.net/?f=A_g%3DA_2-A_1%3D2500%5C%20ft%5E2-144%5C%20ft%5E2)
![A_g=2356\ ft^2](https://tex.z-dn.net/?f=A_g%3D2356%5C%20ft%5E2)
Answer:
0.20833333333 or 5/24
Step-by-step explanation:
Hope this helps UwU <33
Answer: 40 stamps
Step-by-step explanation:
Let Maddy = M and Simon = S
Given that maddy had twice as many stamps as simon. That is,
M = 2S ....(1)
After maddy sold 60 stamps, simon had twice as many stamps as maddy. That is,
S = 2( M - 60) .... (2)
Substitutes M for 2S from equation (1) into equation (2)
S = 2( 2S - 60 )
Open the bracket
S = 4S - 120
Collect the like terms
S - 4S = -120
- 3S = - 120
S = 120/3
S = 40
Substitute S into the equation (1)
M = 2 × 40 = 80
Maddy has 80 - 40 = 40 stamp
Therefore, Maddy has 40 more stamps than simon in the beginning.