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lions [1.4K]
3 years ago
14

Identify the range of the parabola y=-(x+4)^2

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
The range is -infinity to infinity
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Consider the function below. f(x) = 6x tan x, −π/2 < x < π/2 (a) find the vertical asymptote(s). (enter your answers as a
Molodets [167]

Answer: Does not exist.

Step-by-step explanation:

Since, given function,  f(x) = 6x tan x, where −π/2 < x < π/2.

⇒ f(x) = \frac{6x sin x}{cosx}

And, for vertical asymptote,  cosx= 0

⇒ x = π/2 + nπ where n is any integer.

But, for any n x is does not exist in the interval ( -π/2, π/2)

Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.


5 0
3 years ago
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Write 841,620 in three different ways.
Oxana [17]
841,620. 841.620. 841-620. 026,148
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3 years ago
Graph the linear inequality X&lt;1
tester [92]
Ohh wow nice, do your own work lazy person
8 0
3 years ago
Math answer homework​
stiv31 [10]

Answer:

2:15 p.m.

Step-by-step explanation:

Starting time                1:40 p.m.

Time on subway       <u>+0:17 </u>

Time off subway          1:57 p.m.

Time walking            <u>+0:18 </u>

Time at apartment       1:75

When the minutes are more than 60, you subtract 60 from the minutes and add 1 to the hours.

 1   :75

+1<u> - :60 </u>

  2 :15 p.m.

Daniel arrived at the apartment at 2:15 p.m.

8 0
3 years ago
Help Please!!<br> What is the value of a?<br><br> Enter your answer in the box.<br><br> a =
Talja [164]

Answer:

a=15

Step-by-step explanation:

By pythagoras' theorem

25²=20²+a²

625=400+a² group like terms

a²=625-400

a²=225

\sqrt{a {}^{2} }  =  \sqrt{225}

therefore a=15

6 0
3 years ago
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