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Travka [436]
1 year ago
10

Product of square of x and cube of y​

Mathematics
2 answers:
snow_tiger [21]1 year ago
8 0

Answer:

x^2y^3

Step-by-step explanation:

\text{Square of}~ x =x^2\\\\\text{Cube of}~ y = y^3\\\\\text{Product} = x^2y^3

artcher [175]1 year ago
7 0

Since the square root of

x=√x

and the cube root of

x=3√x

and their product

=√x × 3√x

= x1/2 × x1/3 [Since, n√a =a 1/n]

=x1/2+1/3 [Since, a^m ×a^n =a^m+n]

=x^3+2 /6

= x 5/6

Therefore, required product is

=√6x5

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Answer:

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Step-by-step explanation:

We need to think backwards to solve this question.

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-x + 4y when x = -4/5 and y = 1/3
Usimov [2.4K]

we have the expression

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substitute the values of x and y in the given expression

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6 0
3 years ago
Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.
podryga [215]

Answer:

a) \frac{72x^5}{9x^7}

b) =\frac{8}{x^2}

c), Yes;8x^2

Step-by-step explanation:

Michael's Weight: 72x^5

Al's weight: 9x^7

a) Ratio of Michael's weight to Al's weight: \frac{72x^5}{9x^7}

b) This ratio simplifies to:  \frac{8\times 9x^5}{9x^5\timesx^2}

                                         =\frac{8}{x^2}

c) Yes, If the exponent in each expression were negative, then we have:

Ratio of Michael's weight to Al's weight: \frac{72x^{-5}}{9x^{-7}}

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