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S_A_V [24]
2 years ago
8

1. Solve *

Mathematics
2 answers:
Mama L [17]2 years ago
7 0

Answer:

x =−8

Step-by-step explanation:

BaLLatris [955]2 years ago
7 0

Answer:

First you simplify by first taking 4 multiply the parentheses: 4 x 3X - 4 x 2 = 12X - 8 =

Then you have to do the same thing at the right side, try figure it out. When u get the answer simplify it by taking. The x to left side and the ordinary numbers to right side(not always). As said try figure it out urself if u need help i got u

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Which ordered pair is a solution to the system?
almond37 [142]

Answer:

I think it is C 8,-4

Step-by-step explanation:

I think

8 0
3 years ago
Need on number 3 plz
Juli2301 [7.4K]

Answer:

Peyton: 6 years old

Matt: 24 years old

Justin: 9 years old

Step-by-step explanation:

P= Peyton   M= Matt   J= Justin

P=J-3

M=4P

J+P+M=39

4J-12=M  4J-12=39-J-P

5J-51=-P    P=J-3

5J-51=-J+3    J=9

P=9-3  P=6

M=4(6)  M=24


6 0
3 years ago
Need help as soon as possible please
Leokris [45]

Answer:

C - 10

Step-by-step explanation:

n is the number of the term

an = -2n+8

a9 = -2*9 +8

a9 = -18+8

a9 = -10

The 9th term is -10

5 0
3 years ago
HELPPP MEE BEST ANSWER GET THE BRAINLIEST!!
Zielflug [23.3K]
1/2= /360 is the correct answer choice
4 0
3 years ago
Read 2 more answers
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, o
Naddika [18.5K]

Answer: E. 1200

Step-by-step explanation:

Given : A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts.

i.e. No. of choices for different salads= 8  -----(1)

No. of choices for different main courses = 5  ----(2)

No. of choices for different desserts = 6

When we choose two different desserts then we use permutation(repeatition not allowed) :

^6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6\times5\times4!}{4!}=6\times5=30----(3)

[∵ No. of ways to choose r things out of n =^nP_r=\dfrac{n!}{(n-r)!} ]

If customers choose one salad, one main course and two different desserts for their meal , then By Fundamental principle of counting (Multiply (1) , (2) and (3)), the number of  different meals are possible :-

8\times5\times30\\\\=1200

Hence, the correct answer is E. 1200 .

8 0
3 years ago
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