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3 years ago

1. Solve *

Mathematics

2 answers:

Mama L [17]3 years ago

7 0

Answer:

x =−8

Step-by-step explanation:

BaLLatris [955]3 years ago

7 0

Answer:

First you simplify by first taking 4 multiply the parentheses: 4 x 3X - 4 x 2 = 12X - 8 =

Then you have to do the same thing at the right side, try figure it out. When u get the answer simplify it by taking. The x to left side and the ordinary numbers to right side(not always). As said try figure it out urself if u need help i got u

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3 years ago

Solve the following equation:<br> a) 3x - 9 = 27/ 1 - 5x<br> b) 10x - 1/x = 3

mars1129 [50]

Answer:

A) x=9/2 B) x=-1/5, 1/2

Step-by-step explanation:

3x-9=27/1-5x

3x-9=27-5x

3x-(-5x)-9=27

3x+5x-9=27

8x-9=27

8x=27+9

8x=36

x=36/8

simplify

x=9/2

Answer: x=9/2

-----------------------------

10x-1/x=3

(10x^2-1)/x=3

10x^2-1=3*x

10x^2-1=3x

10x^2-3x-1=0

factor out the trinomial,

find two numbers that when they multiply,

you get the third term, which is -1 in this case.

When you add those 2 numbers, you get the second term,

which is -3 in this case.

(5x+1)(2x-1)=0

apply the zero property from here,

set 5x+1=0 and 2x-1=0 and solve for x.

5x=0-1=-1, x=-1/5,

2x=0+1=1, 2x=1, x=1/2.

So x=-1/5, 1/2.

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3 years ago

An equation with more than one operation is called

exis [7]

Divide subtract multiply addition

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3 years ago

Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.

Ganezh [65]

Answer:

$x + 5y - 2z + 14 = 0$

Step-by-step explanation:

A plane that passes through the point $(x_{0}, y_{0}, z_{0})$ with a normal vector of $(a,b,c)$ has the following equation, initially:

$a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0$

After we solve this, we have

$ax + by + cz + d = 0$

In this problem, we have that:

$(x_{0}, y_{0}, z_{0}) = (-5,-1,2)$

$(a,b,c) = (−1,−5,2)$

$a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0$

$-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0$

$-(x + 5) - 5(y + 1) + 2(z - 2) = 0$

$-x - 5 - 5y - 5 + 2z - 4 = 0$

$-x - 5y + 2z - 14 = 0$

Multplying everything by -1

$x + 5y - 2z + 14 = 0$

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Answer:

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