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Alisiya [41]
3 years ago
15

Can a sequence be both arithmetic and geometric?

Mathematics
1 answer:
artcher [175]3 years ago
4 0
An aritmetic sequence is like this
a_n=a_1+d(n-1) where a1=first term and d=common difference

geometric is a_n=a_1(r)^{n-1} where a1=first term and r=common ratio


can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same

therfor we need to solve d(n-1)=(r)^{n-1}
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?

when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal

the answer is no, a sequence cannot be both aritmetic and geometric
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Answer:

No units

Step-by-step explanation:

The cost function is given by;

C(x)=x^2-20x+35

To find the units manufactured at a cost of $5,560

We equate the C(x) to 5560 and solve for x.

x^2-20x+35 = 5560

x^2-20x+35 - 5560 = 0

x^2-20x - 5525= 0

The discriminant of this equation is negative.

That is,

d =  {( - 20)}^{2}  - 4 \times 1 \times  - 5560 \:  < 0

Hence the equation has no real roots.

This means no units can be produced at $5,560

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Step-by-step explanation:

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divide both sides by 9 to get y by itself

9y/9=90/9

cross out 9 and 9 which becomes 1*1*y=y

90/9=10

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find x by using the substitution method

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sign changes from +70 to -70

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x=-9

answer:

(-9,10)

6 0
3 years ago
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