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PtichkaEL [24]
3 years ago
5

Evaluate 6z + 4x for x = 3 and z = 2*

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer:

24

Step-by-step explanation:

6z+4x

=>6(2)+4(3)

=>12+12

=>24

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A number of robbers were discussing how best to share some stolen rolls of
kupik [55]

Answer:

83

Step-by-step explanation:

Let the number of robbers be x

If they share 6 rolls each, the tota rolls will be 6x and since they have five remainder, the overall total is then 6x+5

In case they share 7 rolls each, it means they have 7x rolls but here they will be less 8 rolls hence 7x-8 is the overall total.

Equating these two

7x-8=6x+5

Arranging similar terms

7x-6x=8+5

x=13

Therefore, the robbers are 13

The rolla they have will be

6(13)+5=83

Or

7(13)-8=83

6 0
3 years ago
What is the value of x?
Ronch [10]

Answer:

x = 10

Step-by-step explanation:

Consecutive angles in a parallelogram are supplementary, thus

∠ A + ∠ B = 180, substitute values

9x + 8 + 8x + 2 = 180, that is

17x + 10 = 180 ( subtract 10 from both sides )

17x = 170 ( divide both sides by 17 )

x = 10

6 0
3 years ago
Read 2 more answers
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
A line passes through the points (2,4) and (5,6) .
Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points (x_1,y_1) and (x_2, y_2)

then the general form y -y_1=m(x-x_1) for linear equations where m is the slope given by:

m =\frac{y_2-y_1}{x_2-x_1}

First calculate slope for the points (2, 4) and (5, 6);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}

then, by point slope intercept form;

y-4=\frac{2}{3}(x-2)

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}

then, by point slope intercept form;

y-6=\frac{2}{3}(x-5)

Yes, the only equation of line from the given options  which describes the given line are;

y-4=\frac{2}{3}(x-2)  and y-6=\frac{2}{3}(x-5)



8 0
3 years ago
What is the first term and explicit rule for the following geometric sequence? 3. 15,75,375, 1,875​
VARVARA [1.3K]

First term: 3

Exiplicit formula:

3/5*5^n or 3x5^n-1

Hope this helps!

7 0
3 years ago
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