All categories

2 years ago

Find the midpoint of the line segment with endpoints (-3, -1) and (7, -5).

Mathematics

2 answers:

Anton [14]2 years ago

4 0

Answer:

M = (2 , -3)

Step-by-step explanation:

M = midpoint

M= ((x1+x2)/2) , ((y1+y2)/2)

we have:

(-3, -1) and (7, -5)

x1 = -3 y1 = -1

x2 = 7 y2= -5

M= ((-3+7)/2) , ((-1-5)/2)

M = (4/2) , (-6/2)

M = (2 , -3)

GaryK [48]2 years ago

3 0

Here you go (2,-3) is the midpoint

You might be interested in

ABCD is a quadrilateral. Three of the angles of ABCD measure 100°, 87, and 106°, respectively. Find the measure of the

ladessa [460]

Answer:

Step-by-step explanation:

The angles in a quadrilateral add up to 360 degrees.

100 + 87 + 106= 293

360 - 293 = 67

8 0

2 years ago

Read 2 more answers

Which expresion is equivalent to -5 -(-7)?<br> HURRY 20 POINTS

grigory [225]

Answer:

<h2>2 (the answer should have a positive sign.)</h2><h2>The equivalent to -5-(-7) is -5+7.</h2>

Step-by-step explanation:

To solve this problem, use the order of operations.

PEMDAS

Parentheses

Exponents

Multiply

Divide

Add

Subtract

$\sf{-5-(-7)=-5+7}$

$\sf{-5+7}$

Add or subtract.

Solve.

$-5+7=2$

$\large\boxed{2}$

So, the correct answer is 2.

3 0

2 years ago

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 24 of them play baseball. There are 3 students who pl

antiseptic1488 [7]

Answer:

$\frac{5}{29}$

Step-by-step explanation:

Let $n(A)$ represent students playing basketball, $n(B)$ represent students playing baseball.

Then, $n(A)=7$ , $n(B)=24$

Let $n(S)$ be the total number of students. So, $n(S)=29$ .

Now,

$P(A)=\frac{n(A)}{n(S)}=\frac{7}{29}$

$P(B)=\frac{n(B)}{n(S)}=\frac{24}{29}$

3 students play neither of the sport. So, students playing either of the two sports is given as:

$n(A\cup B)=n(S)-3\\n(A\cup B)=29-3=26$

∴ $P(A\cup B)=\frac{n(A\cup B)}{n(S)}=\frac{26}{29}$

From the probability addition theorem,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Where, $P(A\cap B)$ is the probability that a student chosen randomly from the class plays both basketball and baseball.

Plug in all the values and solve for $P(A\cap B)$ . This gives,

$\frac{26}{29}=\frac{7}{29}+\frac{24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{7+24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{31}{29}+P(A\cap B)\\\\P(A\cap B=\frac{31}{29}-\frac{26}{29}\\\\P(A\cap B=\frac{31-26}{29}=\frac{5}{29}$

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is $\frac{5}{29}$

6 0

2 years ago

Can anyone help me with number 3 please

Gnoma [55]

Answer:

I think is (B)

4 0

2 years ago

A one year membership to metro gym costs $460. There is a fee of $40 when you join, and the rest is paid monthly. Write an equat

zysi [14]

Answer: The equation that would help members to find how much they would pay per month is

40 + 12x = 460

Step-by-step explanation:

Let x represent the amount of money that members would pay per month.

Let y represent the number of months for which a member uses the gym.

There is a fee of $40 when you join, and the rest is paid monthly. This means that the cost of using the gym for x months would be

40 + xy

A one year membership to metro gym costs $460. Therefore are 12 months in a year. Therefore,

40 + 12x = 460

12x = 460 - 40 = 420

x = 420/12 = 35

The equation that would help members to find how much they would pay per month is

8 0

2 years ago

Find the midpoint of the line segment with endpoints (-3, -1) and (7, -5).​

Find the midpoint of the line segment with endpoints (-3, -1) and (7, -5).