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Tanya [424]
3 years ago
14

Recall that two angles are complementary if the sum of their measures is​ 90°. Find the measures of two complementary angles if

one angle is Seventeen times the other angle.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

5 and 85 degrees

Step-by-step explanation:

Ok, so if 2 angles are complementary, that means when put together they equal 90 degrees.

So, let's say one angle is a.

This means the bigger angle would be 17 times the smaller angle, or 17a.

Now let's make an equation:

a + 17a = 90

Now, we have to combine the like terms:

18a = 90

Now in order to find the smaller angle, we just have to divide by 5:

a = 5

This means that the smaller angle is 5 degrees, but because the bigger angle is 17 times the size, we just multiply 5 and 17 together to get 85 degrees.

Hope this helps :)

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Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
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Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ ,  μ₀ + σ]   contains 95.4 % of all the values of the population

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In our case such intervals become

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ]   ⇒  [ 78 - (0,5)*8 , 78 + (0,5)*8 ]  ⇒[ 74 , 82]

[ μ₀ - σ ,  μ₀ + σ]  ⇒ [ 78 - 8 , 78 +8 ]   ⇒  [ 70 , 86 ]

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]  ⇒ [ 78 - 12 , 78 + 12 ]  ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]    ⇒  [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7  = 0,3 %

Only 0,3 % of population is out of   μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

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