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makvit [3.9K]
2 years ago
11

3h-2(4h-5)=10-5h A-0 B-4 C-infinity many solutions D-no solutions​

Mathematics
1 answer:
Crank2 years ago
7 0

Answer:

Step-by-step explanation:

3h - 8h + 10 = 10 - 5h

-5h + 10 = 10 - 5h

10 = 10

infinitely many solutions

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Write each expression using n as your variable.
frozen [14]
C3=n
N x 2 - 6 + 2
N < (6x8) - 10
8 0
2 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
3 years ago
Read 2 more answers
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
2 years ago
Solve the inequality (-3,-3) (3,-1) on a graph
Firdavs [7]
The first number is x axis while the second is y

5 0
3 years ago
Can anyone help me out here?
Alex_Xolod [135]

Answer:

J. 19.7

Step-by-step explanation:

SOH<em>(</em><em>sine = </em><em>opposite side/hypotenuse)</em> CAH TOA

sin 80° = RS/20

=> 0.985 = RS/20

=> RS = 20 × 0.985 = 19.7

5 0
2 years ago
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