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3 years ago

Help please!!!!!!! and thank you

Mathematics

2 answers:

kondaur [170]3 years ago

8 0

Answer:

2,500

Step-by-step explanation:

brainliest me pls

GarryVolchara [31]3 years ago

5 0

Answer:

2.50000 or 2.5 or 2 1/2

Step-by-step explanation:

You have the number 250,000. you have to get the decimal between 1.00 and 10.00 to do this we are going to move the decimal over left one at a time.

25,000.0

2,500.00

250.000

25.0000 25 is really close but not between 1 and 10 so were going to move the decimal one more time

2.50000

2.50000 is between 1 and 10 so its the anwser we are looking for.

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Sam went 300 feet below sea level. Ken is at an elevation of 100 feet. Write an inequality to compare their location

sattari [20]

-300>100 that is the answer because its below sea level

4 0

3 years ago

Your answer must be simplified. x+5≤−4

PilotLPTM [1.2K]

Answer:

x≤−9

Step-by-step explanation:

x+5≤−4

-4-5=-9

you subtract 5 form each side

therefore x≤−9

hope this helps

4 0

3 years ago

Read 2 more answers

Solve by using the quadratic formula: Simplify

larisa [96]

Answer:

-6 - square root 31, -6 + square root 31

8 0

2 years ago

Read 2 more answers

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

I will mark you brainiest if you can answer this

Korvikt [17]

Answer:

12^4 or 20736

Step by Step Instructions:

really all you have to do is subtract the exponents. 12^7-12^3=12^4, if you want to expand the numbers you can do it that way too. 12^7=35831808, 12^3=1728, 35831808/1728=20736 (which is the same as 12^4)

4 0

2 years ago