Answer:
5.25 miles
Step-by-step explanation:
We are required to determine the distance between Lighthouse A and Lighthouse B in the diagram.
Using Law of Cosines
The distance between lighthouses is 5.25 miles.
Answer:
The regular polygon that she should use is an equilateral triangle
Step-by-step explanation:
The parameters given are;
Interior angles = 0.5 × Exterior angles
Exterior angles of a regular polygon = 360/n
Sum of interior angles of a regular polygon = (n - 2) × 180
Where n = the number of sides
Therefore, the sum of exterior angles of a regular polygon = 360°
Hence we have;
(n - 2) × 180 = 360/2 = 180
n - 2 = 180/180 = 1
n = 1 + 2 = 3 which is a three sided regular polygon or an equilateral triangle
Therefore, the regular polygon that she should use is an equilateral triangle
Answer: Answer is $21
Step-by-step explanation:
Using the equation C = P + (P)(T)
where P= $20
T= 5%; 5/100 = 0.05
Substitute the figures in the equation,
$20 + $20 (0.05)
Apply BODMAS and open bracket first
$20 + $1
= $21
Answer: y=-6
Step-by-step explanation:
y = -4 when x = 1
find y when x = 3
y=-4 x=1
y=-5 x=2
y=-6 x=3
im not sure if this is right so I’m sorry
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
