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taurus [48]
3 years ago
8

What information is needed to calculate acceleration?

Physics
2 answers:
aleksley [76]3 years ago
4 0

The correct answer to the question is : B) Change in velocity and time.

EXPLANATION:

Before going to answer this question, first we have to understand acceleration of an object.

The acceleration of an object is defined as the rate of change of velocity i.e the change in velocity per unit time.

Mathematically acceleration a = \frac{dv}{dt}

dv is the change in velocity, and dt is the time taken by an object.

Hence, change in velocity and time are taken in order to calculate the acceleration of an object.

Gre4nikov [31]3 years ago
3 0

B change in velocity and time

(metres per second) per second

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what is the cost of monthly (30 days) electric bill of ana if her city's cost of electricity is 0.05$ per kwh and she uses three
Serjik [45]

Answer:

1kW = 1000W

600W = 0.6kW

Cost of electric bill = 0.6kWh × 24 × 30 × $0.05

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8 0
2 years ago
What was Robert Boyle's most famous discovery about gases​?
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Answer:

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Explanation:

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4 0
3 years ago
Autobus porusza się ze stałą prędkością 54 km/h Oblicz w jakim czasie przebędzie drogę 450 m
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Answer:

Autobus porusza się ze stałą prędkością 54 km/h Oblicz w jakim czasie przebędzie drogę 450 m

3 0
2 years ago
At which of the above boundries is sea floor destroyed
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Hope it helps!!
7 0
3 years ago
Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74
sweet-ann [11.9K]

Answer: 62.7^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed= 16.7 kJ = 16700 J  (1kJ=1000J)

m= mass of benzene = 225 g

c = specific heat capacity = 1.74 J/gK

Initial temperature of the water = T_i = 20.0°C  = 293 k  0^0C=273K

Final temperature of the water = T_f  = ?

Change in temperature ,\Delta T=T_f-T_i

Putting in the values, we get:

16700=225\times 1.74\times (T_f-293)

T_f=335.6K=62.7^0C

The  final temperature will be 62.7^0C

8 0
3 years ago
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