Answer: 3.63 km/s
Explanation:
The escape velocity equation for a craft launched from the Earth surface is:
Where:
is the escape velocity
is the Universal Gravitational constant
is the mass of the Earth
is the Earth's radius
However, in this situation the craft would be launched at a height over the Eart's surface with a space elevator. Hence, we have to add this height to the equation:
Finally:
Answer:
The net force applied to the car is zero.
Explanation:
We are given that a car is moving to the left with constant velocity.
When the car moving with constant velocity
Then, the final velocity=Initial velocity
Change in velocity=Final velocity- initial velocity=0
When change in velocity is zero then , acceleration of car
When acceleration is zero then, By Newtons second law
The net force applied on the car will be zero.
Option C:The net force applied to the car is zero.
Answer:
Time - taken = 2.5 s
deceleration= -8 m/s²
Solution:
Given:
speed, v = 8 m/s
distance, d = 20m
To Find:
deacceleration = ?
As we know speed is defined as
v = d/t
plugging in the values
t = 20/ 8
t = 2.5s
Now from deceleration formula
a = - v/ t
a = - 20/ 2.5
a = - 8 m/s²
Thus, the time taken and acceleration is 2.5 s and -8 m/s²
respectively.
Learn more about deceleration here:
brainly.com/question/13354629
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Given constant acceleration, we can get the final position of an object in terms of both its initial velocity and its acceleration using one of the equations of motion.
The equation that we will use is:
Xf = Xi + Vi*t + (1/2)*a*t^2
where:
Xf is the final position of the object
Xi is the initial position of the object
Vi is the initial velocity of the object
t is the time
a is the constant given acceleration
The time it takes for the key to fall 44 m is
(notice I'm taking the downward direction to be positive)
The boat, moving at a presumably constant speed, then has 3.0 s to travel 19 m to the point of impact, which means its speed must be