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Vadim26 [7]
3 years ago
11

Momentum is a vector quantity which means it has both ___________________ and _____________

Physics
2 answers:
Damm [24]3 years ago
6 0
<span>magnitude and direction</span>
DIA [1.3K]3 years ago
4 0
Direction and magnitude
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It has a flexible vertibrae which allows it to move faster and fit into places . Plus it also allows it to get its prey easier
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3 years ago
Green light (λ = 566 nm) strikes a single slit at normal incidence. Part A
VARVARA [1.3K]

Answer:

755 x 10⁻⁷ m

Explanation:

D = distance of screen

=2.  m

d is width of slit = ?

wave length λ = 566 nm

Width of central maxima = 2 λD /d

= 3.00 x 10⁻² =2 λD /d

d=\frac{2\times566\times10^{-9}\times2}{3\times10^{-2}}

= 754.67 x 10⁻⁷ m .

= 755x 10⁻⁷ m

8 0
3 years ago
What is the name of the ionic compound Cs2S
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The answer is cesium oxide
3 0
3 years ago
Read 2 more answers
A 0.5 kg block slides down a frictionless semicircular track from a height, h, and collides with a second 1.5 kg block at the bo
Ede4ka [16]

Answer:

h' = 0.062\cdot h

Explanation:

The speed of the 0.5 kg block just before the collision is found by the Principle of Energy Conservation:

U_{g} = K

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot h}

v \approx 4.429\cdot \sqrt{h}

Knowing that collision is inelastic, the speed just after the collision is determined with the help of the Principle of Momentum Conservation:

(0.5\,kg) \cdot (4.429\cdot \sqrt{h}) = (2\,kg)\cdot v

v = 1.107\cdot \sqrt{h}

Lastly, the height reached by the two blocks is:

K = U_{g}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot h'

h' = \frac{v^{2}}{2\cdot g}

h' = \frac{(1.107\cdot \sqrt{h})^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

h' = 0.062\cdot h

3 0
3 years ago
A gas is confined to a vertical cylinder by a piston of mass 2 kg and radius 1 cm. When 5J of heat are added, the piston rises b
Anarel [89]

The work done by gas is 0.753 J and change in internal energy is 4.247J

So we are given that mass is 2kg , radius 1 cm and the amount of heat is 5 cm

The piston raised by 2.4cm

As we know that Work done is PΔV

Where ΔV is change in volume

Therefore ΔV =  πr^2 h = π x (.01)^2 x .024 =7.53×10^(-6)m^3

Here pressure is 10^5 pa

So W = 10^5\times7.53\times10^-(6)

Therefore W = 0.753 J

Now coming to change in internal energy

Change in Internal Energy = Heat Added - Energy lost in work

∴ 5J - 0.753 J = 4.247J

Hence the change in internal energy is 4.247 J

Learn more about Work done here

brainly.com/question/16951089

#SPJ1  

6 0
2 years ago
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