Answer:
<DFA
Step-by-step explanation:
When combined (<DFA and <DFE), they'll form 90 degrees which will make them complementary
There are 30 students all together, and 4 of them are Freshman girls (Freshwomen ?). So the probability that one randomly chosen student is a Female Frosh is 4/30 = 2/15.
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
x = 30
Step-by-step explanation:
1/2(x+6) = 18
Distribute
1/2 x + 3 = 18
Subtract 3 from each side
1/2x +3-3 = 18-3
1/2x = 15
Multiply each side by 2
1/2x*2 = 15*2
x = 30