Show me how to graph f(x)=3/2 x + 2
1 answer:
y = (3x)/2 + 2
Slope = 3/2
y-intercept = 2
The first point is y-intercept when x = 0 = (0,2). Now according to our slope we move 3 up (Why up? Because it's positive) and 2 right (Why right? Because it's positive).
When you move 3 up from (0,2), you get (0,5) and move 2 right which is (2,5).
Remember: slope = change in y / change in x
Points: (0,2) and (2,5)
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Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer