Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
Answer:
3(x-1)
Step-by-step explanation:
you need to out the x minus 1 in brackets as you multiply the whole thing by 3
Let
s-------> the amount of money Layla deposits
we know that
![25\%= \frac{25}{100}=0.25](https://tex.z-dn.net/?f=25%5C%25%3D%20%5Cfrac%7B25%7D%7B100%7D%3D0.25)
![50\%= \frac{50}{100}=0.50](https://tex.z-dn.net/?f=50%5C%25%3D%20%5Cfrac%7B50%7D%7B100%7D%3D0.50)
![s\geq 0.25*\$200\\ s \geq\$50](https://tex.z-dn.net/?f=s%5Cgeq%200.25%2A%5C%24200%5C%5C%20s%20%5Cgeq%5C%2450)
![s\leq 0.50*\$200 \\ s\leq \$100](https://tex.z-dn.net/?f=s%5Cleq%200.50%2A%5C%24200%20%5C%5C%20s%5Cleq%20%5C%24100)
so
![\$50 \leq s \leq \$100](https://tex.z-dn.net/?f=%5C%2450%20%5Cleq%20s%20%5Cleq%20%5C%24100)
therefore
<u>the answer is</u>
![\$50 \leq s \leq \$100](https://tex.z-dn.net/?f=%5C%2450%20%5Cleq%20s%20%5Cleq%20%5C%24100)
She could deposit ![\$50](https://tex.z-dn.net/?f=%5C%2450)
She could deposit ![\$75](https://tex.z-dn.net/?f=%5C%2475)