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3 years ago

I don't understand this, at all.

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

5 0

You have to figure out the top first and that answer is what you wil be dividingt the bottom answer from....

ikadub [295]3 years ago

3 0

$\frac{14 x^{2} + 24x}{2 x^{2} + x - 3}
$
<span>
$\frac{7x(2x + 3)}{(2x + 3)(x - 1)}$ </span>

$\frac{7x}{(x - 1)}$

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System of equations- does this have one solution, many solutions or no solution

Alla [95]

Answer:

One solution

Step-by-step explanation:

Let's rewrite y = 6 - 3x as y = -3x + 6

Looking at these two equations, we can see they share a y-intercept

Making our solution 6

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We also know there aren't no solutions because the lines are not parallel (same slopes with difference y-intercepts)

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Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

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