Find the measure of angle A. 95° 14x + 1 A 14x

The recipe calls for 2/3 cup of sugar and 3/4 cup of flour. What is the total amount of dry goods that the recipe calls for you

Tju [1.3M]

Answer:

i- umm- its, well i got two answers n this question as well, but umm, i think its

1 5/12 maybe

Step-by-step explanation:

5 0

3 years ago

What the answer guys?

Inga [223]

I dont understand what you mean by whats the answer. please if you can kindly place a question, then maybe i will be able to help you. please and thank you.

3 0

3 years ago

If a kitten weighs 4 pounds what is the approximate mass of the kitten in kilograms

Tatiana [17]

It is around 1.81 kilograms

5 0

3 years ago

Can anybody help me with this plzzz‼️ (If answer is correct i will cashapp you $6)

Ganezh [65]

Step-by-step explanation:

h(x) = 3. g(x) + 5

x= -1 h(x) = 3×8 + 5= 29

x= 0h(x) = 3×5 + 5= 20

x= 2 h(x) = 3×1 + 5= 8

x= 5 h(x) = 3×-5 + 5= -10

4 0

3 years ago

Read 2 more answers

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago