Answer:
lies in the shaded regions of both the top and bottom inequalities
Step-by-step explanation:
For a point to be a solution of two inequalities, it must lie in both solution sets. It ...
lies in the shaded regions of both the top and bottom inequalities
Answer:
9
Step-by-step explanation:
Given
p(x) = 5x² - 3x + 7 ← substitute x = 1
p(1) = 5(1)² - 3(1) + 7 = 5(1) - 3(1) + 7 = 5 - 3 + 7 = 9
Certin, because they can be any two cards.
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the line y = x
a point (x, y ) → (y, x ) , thus
(- 1, - 2 ) → (- 2, - 1 )
(1, 1 ) → (1, 1 )
(4, - 3 ) → (- 3, 4 )
Answer:
Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.
Y = 3x^x (-∞, 0) and (∞, ∞).
Y = 3x^-x (-∞, ∞) and (∞, 0).
Step-by-step explanation:
The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".
When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.
For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.
Here's an image of the graphs: