It is given thatΔ QRS ≅Δ TUV
Out of all the given options
(C) QS= TV [C P C T}
(D) QR =TU
(E) S = V
(F) R= U
C, D,E, F are correct options.
Because when two triangles are congruent their corresponding parts are equal.
CPCT means corresponding parts of congruent triangles.
All these options are congruent by CPCT.
Side QR is congruent to TU.
Side Q S is congruent to TV.
Angle S is Congruent to Angle V.
Angle R is congruent to Angle U.
The meaning of congruency of shapes is that the two or many more shapes are identical.
9514 1404 393
Answer:
true
Step-by-step explanation:
Using the order of operations to evaluate the expressions, we have ...
8 + 5(8) ≥ 9(5)
8 +40 ≥ 45
48 ≥ 45 . . . . . true
Step-by-step explanation:
the image u have shared is too much covered by focus light send it again
Answer:
- x = ±√3, and they are actual solutions
- x = 3, but it is an extraneous solution
Step-by-step explanation:
The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...
... x^2(6x -18) = (2x -6)(9)
... 6x^2(x -3) -18(x -3) = 0
...6(x -3)(x^2 -3) = 0
... x = 3, x = ±√3
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Alternatively, you can subtract the right side of the equation and collect terms to get ...
... x^2/(2(x -3)) - 9/(6(x -3)) = 0
... (1/2)(x^2 -3)/(x -3) = 0
Here, the solution will be values of x that make the numerator zero:
... x = ±√3
_____
So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.
_____
<em>Comment on the graph</em>
For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.
Answer:
she spent 75%
Step-by-step explanation: