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Arte-miy333 [17]
3 years ago
15

Unit of Measurement, a punk/disco band, was signed up to play a benefit

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0
D because they played for two days so that makes you multiply the number of seconds by the same number
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The city has a section of land that is 3,694.7 feet long. The city wants to partition this lengths to form 10 equal-sized garden
Soloha48 [4]

Answer:

  369.47 ft

Step-by-step explanation:

Each plot is 1/10 of the total length, so has length ...

  (3694.7 ft)/10 = 369.47 ft

5 0
3 years ago
So I need help with this. Why Do we seat?​
r-ruslan [8.4K]

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When we stand our muscles are working a little bit, and if we're moving around, our muscles are working even more, so we sit down to take a little bit of a break, but the problem starts when we sit down for too long. ... If we sit for too long, it's not good for our heart.

Step-by-step explanation:

hope this helps

6 0
2 years ago
Help please I don’t understand
FromTheMoon [43]

Answer:

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3 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
2 years ago
6w = 21<br><br> Solve for w<br><br> Please show steps
brilliants [131]

Answer:

w=21/6

w=3.5

Step-by-step explanation:

I hope it's helps you

4 0
3 years ago
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