The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
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Answer 2. You just have to find wants similar and put it out front and then leave wants left in parentheses
Answer:
The solution is given below:
Step-by-step explanation:
The computation is shown below:
= 19 + 7 divided by 2 - 5
= (19 + 7) ÷ (2) - 5
= 26 ÷ 2 - 5
= 13 - 5
= 8
Hence, after solving this the value would be 8
Therefore it is equal to the 8
Hence, the given statement is true
Answer:
a). m∠AED = 70°
b). x = 10°
Step-by-step explanation:
a). Quadrilateral ABDE is a cyclic quadrilateral.
Therefore, by the theorem of cyclic quadrilateral,
Sum of either pair of opposite angle is 180°
m(∠AED) + m(∠ABD) = 180°
m(∠AED) = 180° - 110°
m(∠AED) = 70°
Since, ∠AED ≅ ∠EAD
Therefore, m∠AED = m∠EAD = 70°
b). By triangle sum theorem in ΔABD,
m∠ABD + m∠BDA + m∠DAB = 180°
110° + 40° + m∠DAB = 180°
m∠DAB = 180° - 150°
m∠DAB = 30°
m∠BAE = m∠EAD + m∠BAD
= 70° + 30° = 100°
By angle sum theorem in ΔACE,
m∠EAC + m∠AEC + m∠ACE = 180°
100° + 70° + x° = 180°
x = 180° - 170°
x = 10°
Answer:
they both charge the same cost per linear feet
Step-by-step explanation:
It appears that each company has a base charge for installation, which is the dollar value where each line begins at the y-axis. Both lines have the same slope and if you count, the cost is $75 per 5 linear feet.
