Answer:
The work done in stretching it from its natural length to 14 in. beyond its natural length is W=8.17 ft-lb.
Step-by-step explanation:
We know that a force of 8 lb is required to hold a spring stretched 8 in. beyond its natural length.
This let us calculate the spring constant k as:

We know that work is, in an scalar form, the product of force and distance.
The force F is equal to the spring constant multiplied by the distance from the natural length.
Then, as the force changes with the distance from the natural length, we have to calculate integrating:


Answer:
12150 ft^3
Step-by-step explanation:
= (45)(20)(10) + (350)(9)
= 9000 + 3150
= 12150 ft^3
Answer:
C
Step-by-step explanation:
f(x) × g(x)
= 5x(x + 11) = 5x² + 55x, thus
h(x) = 5x² + 55x → C