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leonid [27]
3 years ago
7

A researcher asks participants to estimate the calories they consume in a meal. The researcher records the following estimates:

450, 426, 310, 500, and 220. If the researcher removes the estimate of 220 (perhaps because the participant drops out of the study), then the value of the mean will:_____________
Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

Increase

Step-by-step explanation:

The researcher records the following estimates: 450, 426, 310, 500, and 220.

The mean of these estimates is derived below.

Mean = (450+426+310+500+220)/5

=1906/5=381.2

If the researcher removes the estimate of 220.

The mean of the other numbers will be:

Mean =(450+426+310+500)/4

=1686/4=421.5

By comparison of the two mean, we can see that the value of the mean will increase.

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david a high school senior was wondering if the cost of attending college is worth the expense. he collected the following data
dimulka [17.4K]

Answer:

Part A: Based on the information collected, who will have the higher mean annual salary?  

College graduates have a higher mean by about $20,000

 

Part B: If you were to graph this data, what would be important to consider?  

The data should be graphed on the same axis and scale so comparisons are possible

Step-by-step explanation:

5 0
3 years ago
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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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Step-by-step explanation:

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