The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer:
what? I don't get
Step-by-step explanation:
X=-b/2a=4/14=2/7
Plug this value back into the function to find the corresponding Y value
Combine like terms.
-14cd + 15cd - 15cd = -14cd
-2c²d² + 9c²d² = 7c²d²
7c²d² - 14cd is your answer
hope this helps
Answer:
4217
Step-by-step explanation:
7.07(10^2)+3.51(10^3)
(7.07)(100)+3.51(10^3)
707+3.51(10^3)
707+(3.51)(1000)
707+3510
4217