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olga55 [171]
3 years ago
11

Arithmetic average of real nonnegative numbers is always smaller than or equal to geometric average. Group of answer choices Tru

e False
Mathematics
1 answer:
noname [10]3 years ago
4 0

Answer:

False

Step-by-step explanation:

Actually, the arithmetic average (or mean) is always greater or equal than the geometric average. This is known as the Arithmetic-Geometric inequality (AM inequality). Let a,b be two real numbers, then the AM inequality states that

\frac{a+b}{2}\geq \sqrt{ab}

To see that the given statement is false, consider a=1, b=3. The arithmetic mean is equal to (1+3)/2=2, and the geometric mean is equal to \sqrt{1\cdot 3}=\sqrt{3} but 2>\sqrt{3}, contrary to the statement (arithmetic>geometric in this case).

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Just substitute a1 = 150 cm and r = 0.74

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