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gayaneshka [121]
3 years ago
14

Multiplication facts

Mathematics
1 answer:
zaharov [31]3 years ago
3 0
- Anything times(x) 1 is ONE
- Anything times 2 always has an even number at the end
On and On 
Here's a picture I got from online.

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How do you know whether to use mean or median when analyzing a one variable data set (box & whisker plot, histogram)... I lo
mart [117]
Median is generally good if you have outliers (data points that are very far off from the majority of the points).

Mean can be used otherwise. 
4 0
3 years ago
Read 2 more answers
A triangle has sides with lengths of 4 yards, 10 yards, and 11 yards. Is it a right triangle?
vodka [1.7K]

Answer:

no

Step-by-step explanation:

for a triangle to be a right triangle, the sum of the square of its legs must equal the square of its hypotenuse

a² + b² = c²

in this problem, 4² + 10² ≠ 11²

16 + 100 ≠ 121

6 0
3 years ago
7. Se llevó a cabo una encuesta de mercado para calcular la proporción de amas de casa que reconocerían el nombre de la marca de
Norma-Jean [14]

Answer:

a) El valor de la proporción de la población = 0.3

b) El intervalo de confianza de 99% de la proporción poblacional = [0.2685, 0.3315]

c) Interprete sus conclusiones.

De los cálculos anteriores, podemos concluir que tenemos un 99% de confianza en que el parámetro de población se encuentra entre 0.2685 y 0.3315 ".

Step-by-step explanation:

a) Halla el valor de la proporción de la población.

El valor de la proporción se calcula mediante la fórmula

p = x / n

donde x = 420

n = número de muestras = 1400

Proporción (p) = 420/1400

= 60/200 = 30/100 = 3/10

= 0.3

b) Construya el intervalo de confianza del 99% para la proporción de población.

La fórmula para el intervalo de confianza para la proporción de población =

p ± z × √p (1 - p) / n

p = 0.3

z = puntuación z para un intervalo de confianza del 99% = 2.576

n = 1400

Por lo tanto:

Intervalo de confianza del 99% = 0.3 ± 2.576 × √0.3(1 - 0.3) / 1400

= 0.3 ± 2.576 × √0.3× 0.7 / 1400

= 0.3 ± 2.576 × 0.0122474487

= 0.3 ± 0.0315494279

Intervalo de confianza del 99% =

0.3 - 0.0315494279

= 0.2684505721

Aproximadamente ≈ 0.2685

0.3 + 0.0315494279

= 0.3315494279

Aproximadamente ≈ 0.3315

Por lo tanto, el intervalo de confianza del 99% = [0.2685, 0.3315]

c) Interprete sus conclusiones.

De los cálculos anteriores, podemos concluir que tenemos un 99% de confianza en que el parámetro de población se encuentra entre 0.2685 y 0.3315 ".

6 0
2 years ago
What is the base and exponent of x^5
Masteriza [31]

Answer:

The base is <em>x</em> and the exponent is 5.

Step-by-step explanation:

Hi there!

x^5

The base is <em>x</em> and the exponent is 5.

<em>x </em>is raised to the exponent of 5.

I hope this helps!

8 0
2 years ago
The dollar value v (t) of a certain car model that is t years old is given by the following exponential function.
dybincka [34]

Answer:

v(0) = 19,900, v(11) = 3,787.36

Step-by-step explanation:

v(0) = 19,900 (0.86)^0 = 19,900 * 1 = 19,000

v(11) = 19,900 (0.86)^11 = 19,900 * 0.190319 = 3,787.36

6 0
3 years ago
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