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Levart [38]
3 years ago
8

4. A cash register contains $10 bills and $20 bills with a total value of $340. If there are 23 bills total, then how many of ea

ch does the register contain?
Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

10+10+10+20+20+20+10+20+20+20+10+20+10+20+20+20+10+10+10+10+10+20+10=340

Anastaziya [24]3 years ago
6 0

There are total 17bills of $20 dollars and 6 for $10 bills.

We get the answer of $20 bills by dividing 340 and 20 then we get 17 then subtract the value from total bills than you get 6 bills for $10 dollars

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The half-life of aspirin is about 3 hours. If someone takes 700mg, how long will it take until less than 50mg is left in that pe
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A new fast-food firm predicts that the number of franchises for its products will grow at the rate dn dt = 6 t + 1 where t is th
yaroslaw [1]

Answer:

The answer is "253"

Step-by-step explanation:

In the given- equation there is mistype error so, the correct equation and its solution can be defined as follows:

Given:

\bold{\frac{dn}{dt} = 6\sqrt{t+1}}\\

\to dn= 6\sqrt{t+1} \ \ dt.....(a)\\\\

integrate the above value:

\to \int dn= \int 6\sqrt{t+1} \ \ dt \\\\\to n= \frac{(6\sqrt{t+1} )^{\frac{3}{2}}}{\frac{3}{2}}+c\\\\\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}+c\\\\

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so the value of  n is:

\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}-3\\\\

when we put the value t= 15 then,

\to n= \frac{(12\sqrt{15+1} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\sqrt{16} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\times 64)}{3}-3\\\\\to n= (4\times 64)-3\\\\\to n= 256-3\\\\\to n= 253

6 0
3 years ago
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