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S_A_V [24]
3 years ago
8

Susie has 3 1/5 pounds Of jellybeans. Julie wants to combined his 2 1/3 Pound bag of licorice with Susie's jellybeans. What woul

d be the total weight of candy when combined
Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

The Total Weight of candy is  5\frac{8}{15} \ pounds.

Step-by-step explanation:

Given:

Amount of Jelly beans Susie have = 3\frac{1}{5} pounds

3\frac{1}{5} can be rewritten as \frac{16}{5}

Also Given;

Julie has amount of licorice =2\frac{1}{3} pounds

2\frac{1}{3} can be Rewritten as \frac{7}{3}

Now Julie wants to combined her bag of licorice with Susie's jellybeans.

Hence the Total weight of candy will be the sum of Amount of Jelly beans and amount of licorice.

Total weight of candy = \frac{16}{5} + \frac{7}{3}

Now making the Denominator common we get;

Total weight of candy = \frac{16\times3}{5\times 3} + \frac{7\times5}{3\times5}= \frac{48}{15} + \frac{35}{15}=\frac{48+35}{15}= \frac{83}{15} \ pounds

\frac{83}{15} \ pounds can be Rewritten as 5\frac{8}{15} \ pounds

Hence The Total Weight of candy is  5\frac{8}{15} \ pounds.

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Answer:

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Step-by-step explanation:

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The answer is<u> D.</u> h+3/j+6.

Step-by-step explanation:

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The equation h + 3 = jk + 6k.

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h + 3 = jk + 6k

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<em> </em><em>Base=9cm</em>

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