All categories

3 years ago

The population of a city is 578,992. The land area of the city is 67.2 mi².

Mathematics

2 answers:

Alex3 years ago

7 0

Answer:

The answer is 8616

Step-by-step explanation:

You solve it by dividing:

578,992/67.2 mi² = 8616.9 Round that and you get your answer.

Plz mark as brainliest

Hope this helped!

Inessa05 [86]3 years ago

5 0

Sorry man I don't know if im write but try 28.78

You might be interested in

Find the mode, median and mean of the following data and match them with their appropriate result provided below. 3, 12, 11, 7,

kobusy [5.1K]

How to get the mode:

- To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode.

{3, 4, 5, 5, 6, 7, 10, 11, 12} => 5

How to get mean:

- The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words, it is the sum divided by the count.

(3 + 12 + 11 + 7 + 5 + 5 + 6 + 4 + 10) / 9

=> 63 / 9

=> 7

How to get median:

- To find the median, first order the numbers from smallest to largest. Then find the middle number

3, 4, 5, 5, 6, 7, 10, 11, 12

So the middle number is 6

------------------------------------------------

Mean: 7

Median: 6

Mode: 5

4 0

3 years ago

GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT

Ber [7]

Answer:

87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

(2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

(1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0

4 years ago

Who has the better biking rate? Josh bikes 24 miles in 20 minutes and Maddie bikes 39 miles in 30 min

umka21 [38]

Maddie just go with it

4 0

3 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago

Which of the following situations WOULD NOT represent a binomial application? A. Choosing a card randomly from a standard deck a

SVETLANKA909090 [29]

Answer:

Choosing a card randomly and noting its suit

Step-by-step explanation:

Choosing a card randomly and noting its suit

This is because binomial distributions only work for bernoulli trials (a trail in which there are only two outcomes)

4 0

3 years ago