When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
Answer:
$5.75
Step-by-step explanation:
14.25 divided by 5= 2.85
2.85+2.85=5.75
Answer:
2.45 gallons of gasoline were in the tank before.
Step-by-step explanation:
Consider the provided information.
The tank can hold 
gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of gasoline to fill it completely.
We need to find: How many gallons of gasoline were in the tank before Javier added some?
For this, we need to subtract added gallons of gasoline from the capacity of the tank.
Hence, 2.45 gallons of gasoline were in the tank before.
Mrs geyer is gonna have to get a new membership to the gym which is 60$ of ever day
Answer:
6 and -14
Step-by-step explanation:
Area of the triangle = 1/2 ab
42 = 1/2 (x)(x+8)
42 *2 = x(x+8)
84 = x²+8x
x²+8x-84 = 0
x²+14x-6x-84 = 0
x(x+14)-6(x+14) = 0
x-6 = 0 and x+14 = 0
x = 6 and -14
Hence the values of x are 6 and -14
