Multiplying both sides of a rational equation by a variable expression introduces the possibility of extraneous solutions. Therefore, we must check the solutions against the set of restrictions. If a solution is a restriction, then it is not part of the domain and is extraneous.
Answer:
(-3,2)
Step-by-step explanation:
If it moved 3 units left, that means the new point's x-coordinate is -3.
If it moved 2 units up, that means the new point's y-coordinate is 2.
Therefore, if the new point's x-coordinate is -3 and y-coordinate is 2, we can represent the point as (-3,2)
Answer:
Only x=-2 is an extraneous solution is the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
that would be the anwer
Answer:
p = 1.5 and q = 9
Step-by-step explanation:
Expand the right side then compare the coefficients of like terms on both sides, that is
4(x + p)² - q ← expand (x + p)² using FOIL
= 4(x² + 2px + p²) - q ← distribute parenthesis
= 4x² + 8px + 4p² - q
Comparing coefficients of like terms on both sides
8p = 12 ( coefficients of x- terms ) ← divide both sides by 8
p = 1.5
4p² - q = 0 ( constant terms ), that is
4(1.5)² - q = 0
9 - q = 0 ( subtract 9 from both sides )
- q = - 9 ( multiply both sides by - 1 )
q = 9
