Check the attached file for the answer.

$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
It would be 1444
hope this helps
We know that she spent $39, and has 3/4 of the original amount left. Our goal is to find the original amount. We can use the equation. x - 39 = 3/4x. Once we subtract x on the left hand side, we get -39 = -1/4x. Once we multiply -39 by -4, we get 146. She originally had $156.