Answer:
The length of the segment AB is 18.8 cm or 1.88 dm
Step-by-step explanation:
<u><em>The question in English is</em></u>
Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm
we have that
----> by Addition segment postulate
substitute the given values in centimeters
Remember that
so
solve for AB
Convert to dm
therefore
The length of the segment AB is 18.8 cm or 1.88 dm
Answer:
Step-by-step explanation: The reason is is because when adding and subtracting integers, you flip the operation sign that will be used to solve the problem.So when you flip the sign of this equation, you subtract. So that's how your answer was 11/17. Also it is positive because the biggest number is positive so that is what the solution will be.
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We know that 60 minutes = 1 hour and 1 mile = 5280 feet. We just need to multiply and simplify:
651 miles/hour = 651 *5280/60 feet/minutes = 651*88 feet/minutes = 57288 feet/minutes
470,925.8 in expanded form is ...
400,000 + 70,000 + 900 + 20 + 5 + 0.8
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<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
