Given:
The area of the big card = 384 square in.
And the side of the big card = 24 in.
The side of the small card = 8 in.
Required:
Use this to find the area of the small card.
Explanation:
The given formula is:fi
![\frac{Area\text{ of big card}}{Area\text{ of small card}}=(\frac{side\text{ of big card}}{side\text{ of small card}})^2](https://tex.z-dn.net/?f=%5Cfrac%7BArea%5Ctext%7B%20of%20big%20card%7D%7D%7BArea%5Ctext%7B%20of%20small%20card%7D%7D%3D%28%5Cfrac%7Bside%5Ctext%7B%20of%20big%20card%7D%7D%7Bside%5Ctext%7B%20of%20small%20card%7D%7D%29%5E2)
Substitute the given values in the formula:
![\begin{gathered} \frac{384}{Area\text{ of small card}}=(\frac{24}{8})^3 \\ \frac{384}{Area\text{ of small card}}=(3)^2 \\ \frac{384}{Area\text{ of small card}}=9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B384%7D%7BArea%5Ctext%7B%20of%20small%20card%7D%7D%3D%28%5Cfrac%7B24%7D%7B8%7D%29%5E3%20%5C%5C%20%5Cfrac%7B384%7D%7BArea%5Ctext%7B%20of%20small%20card%7D%7D%3D%283%29%5E2%20%5C%5C%20%5Cfrac%7B384%7D%7BArea%5Ctext%7B%20of%20small%20card%7D%7D%3D9%20%5Cend%7Bgathered%7D)
![\begin{gathered} Area\text{ of small card = }\frac{384}{9} \\ =42.67\text{ in}^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Area%5Ctext%7B%20of%20small%20card%20%3D%20%7D%5Cfrac%7B384%7D%7B9%7D%20%5C%5C%20%3D42.67%5Ctext%7B%20in%7D%5E2%20%5Cend%7Bgathered%7D)
Final Answer:
The area of the small card is
Answer:
y = 5/2x + 3
Step-by-step explanation:
Given the point (0, 3) and the slope of 5/2, we can plug those values into the following slope-intercept form:
y = mx + b
where m = slope = 5/2
b = y-intercept (the point in the graph where it crosses the y-axis; it is also value of y when x = 0). The y-coordinate of the given point contains the y-intercept, (0, 3). Therefore, the y-intecept = 3.
Putting these factors together, we can write the following equation:
y = 5/2x + 3
Answer:
<h2>
-9/22t</h2>
Step-by-step explanation:
Just do -4/22-5/22 = 9/22 and just add a t, which is 9/22t.
If you have 10 red balls, you have blue balls in proportion 3:2, so you have 15 blue balls. Moreover, you have white balls in proportion 8:2=4:1, so you have 40 white balls.
Removing 10 white and blue balls causes you to have 30 white, 10 red and 5 blue balls.
Since 30=5*6 and 10=5*2, the new proportion of white, red and blue balls is 6:2:1.
Answer:
35
Step-by-step explanation: