In a certain Algebra 2 class of 23 students, 11 of them play basketball and 13 of them play baseball. There are 8 students who p
lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
1 answer:
Answer:
9/23
Step-by-step explanation:
Of the 23 students, 9 play both baseball and basketball. The probability of choosing one of those is 9/23.
___
Let A represent basketball, and B represent baseball. Then ...
P(A or B) = P(A) +P(B) -P(A and B)
Since 8 students play neither sport, we have ...
1 -8/23 = 11/23 +13/23 -P(A and B)
15/23 = 24/23 -P(A and B)
P(A and B) = (24 -15)/23
P(A and B) = 9/23
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Step-by-step explanation:
Given that a convenience store regularly buys mangoes from a wholesale dealer. For every shipment, the manager randomly inspects five mangoes from a box containing 20 mangoes for damages due to transportation. Suppose the chosen box contains exactly 2 damaged mangoes.
In the selected box 18 good mangoes and 2 damaged mangoes are there
a) Find the probability that the first mango is not damaged.
= prob of selecting 1 from any one of 18 good mangoes =
b. Find the probability that neither of the mangoes is damaged. =
Prob of selecting 2 from 18 good mangoes
=
c. Find the probability that both mangoes are damaged.
= Prob of selecting 2 from 2 bad mangoes
=