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elena-14-01-66 [18.8K]
2 years ago
6

In a certain Algebra 2 class of 23 students, 11 of them play basketball and 13 of them play baseball. There are 8 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Mathematics
1 answer:
Artemon [7]2 years ago
7 0

Answer:

  9/23

Step-by-step explanation:

Of the 23 students, 9 play both baseball and basketball. The probability of choosing one of those is 9/23.

___

Let A represent basketball, and B represent baseball. Then ...

  P(A or B) = P(A) +P(B) -P(A and B)

Since 8 students play neither sport, we have ...

  1 -8/23 = 11/23 +13/23 -P(A and B)

  15/23 = 24/23 -P(A and B)

  P(A and B) = (24 -15)/23

  P(A and B) = 9/23

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If the discriminant is positive how many solutions are there
ddd [48]

Answer:

b^2-4ac>0 yields 2 real roots

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

• b^2-4ac>0 yields 2 real roots

• b^2-4ac=0 yields 1 real root

• [tx]b^2-4ac<0[/tex] yields no real roots

Example:

4x^2-7x+2=0 where a=4, b=-7, and c=2

b^2-4ac=(-7)^2-4(4)(2)=49-32=17.

It has 2 real roots


7 0
3 years ago
PLEASE HELP!!!! Show steps and explain how to get the answer please <br><br> Solve 5x-16=4(x-8)-3x
Anvisha [2.4K]

5x-16 = 4(x-8)-3x

first expand what is in parenthesis

4(x-8) = 4x-32

 so now you have 5x-16 = 4x-32-3x

subtract 3x from 4x on the right side of equation 4x-3x = x

5x-16 = x -32

subtract 1x from each side to get

4x-16 = -32

add 16 to both sides to get 4x=-16

x = -16/4 = -4

x=-4

6 0
3 years ago
Read 2 more answers
What is the median of this data <br><br> 10,11,14,10,14,11,15
marta [7]

<h3>Answer-</h3>

I think 11 is the median for the data.

8 0
2 years ago
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I need to find the area of the figure
Ronch [10]
The area of the figure is 161
3 0
3 years ago
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Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
Read 2 more answers
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